(2x+1)(3x^2*20x-7)=0

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Solution for (2x+1)(3x^2*20x-7)=0 equation:


Simplifying
(2x + 1)(3x2 * 20x + -7) = 0

Reorder the terms:
(1 + 2x)(3x2 * 20x + -7) = 0

Reorder the terms for easier multiplication:
(1 + 2x)(3 * 20x2 * x + -7) = 0

Multiply 3 * 20
(1 + 2x)(60x2 * x + -7) = 0

Multiply x2 * x
(1 + 2x)(60x3 + -7) = 0

Reorder the terms:
(1 + 2x)(-7 + 60x3) = 0

Multiply (1 + 2x) * (-7 + 60x3)
(1(-7 + 60x3) + 2x * (-7 + 60x3)) = 0
((-7 * 1 + 60x3 * 1) + 2x * (-7 + 60x3)) = 0
((-7 + 60x3) + 2x * (-7 + 60x3)) = 0
(-7 + 60x3 + (-7 * 2x + 60x3 * 2x)) = 0
(-7 + 60x3 + (-14x + 120x4)) = 0

Reorder the terms:
(-7 + -14x + 60x3 + 120x4) = 0
(-7 + -14x + 60x3 + 120x4) = 0

Solving
-7 + -14x + 60x3 + 120x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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